the common ratio is 0.99 i belive that is the answer
An = a1 r^(n-1)
here a1 = 6 and r = 3 so
a7 = 6 * 3^(7-1)
= 4374 answe
135 mg*1g/1000mg*10dg/1g=1.35 dg
Given:
The train has 6 passenger cars
Each car has 4 columns
And 1 column hold 50 passengers
So, total of seats will be = 6 * 4 * 50 = 1200
Now, there are 25 empty seats,
therefore the correct equation will be :
Number of seats per car: 4 × 50 = 200
Total number of seats: 200 × 6 = 1,200
Number of passengers: 1,200 − 25 = p
