The time required for one wing beat is 5 milliseconds.
<em><u>Explanation</u></em>
Lets assume, the time required for one wing beat is 
seconds
So, the time required for 200 wing beat 
seconds
Given that, the honeybee flaps its wings 200 times per 1 second. So...
So, the time required for one wing beat is 5 milliseconds.
Answer:
A)7
B)14
C)20
D)18
Step-by-step explanation:
For example 2/5 of 80
2/5 x 80/1 =32 Cross cancel
Answer: 707 km/h
Step-by-step explanation:
let c = speed of current
16.5 + c = speed of sailboat downstream
16.5 - c = speed of sailboat upstream
distance = travel time * speed
﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋﹋
2(16.5 + c) = 5(16.5 - c)
33 + 2c = 82.5 - 5c
7c = 49.5
c = 7.07 km/h
First of all we need to know that 1 yard has 3 feet inside of it
but in order to find 24 yards we would have to multiply by 3 sooo
24 x 3 = 72
so that means there are 72 feet in 24 yards.
In other words the answer is D:)
hope this helps:P
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