Please answer right away

A rectangle is formed by placing two identical squares side by side

julsineya [31]

Answer:

200

Step-by-step explanation:

If there are 2 squares next to eachother with the same area, then their perimeter is 6*sidelength.

60 = 6*sidelength

10 = sidelength

Square the sidelength to find the area of the square. 10^2 = 100

Multiply that by 2 to find the area of the rectangle. 100*2 =

200

4 0

4 years ago

2x+5y how do i simplify this or do i just leave this as that

zheka24 [161]

Since they are not like terms (not the same variables) you cannot simply so you leave it like that.✨ This applies for addition and subtraction only. It’s different with multiplication and division.✨

8 0

2 years ago

- Let y represent the width of a rectangle and let x represent the rectangle's lengu.

valentina_108 [34]

Answer:

Length: 21 cm and Width: 6cm

Step-by-step explanation:

Let $y$ be the width and $x$ length of the rectangle. We know:

$x = 4y -3$ -------- eq. 1

$54 = 2x + 2y$ (Perimeter of the rectangle) ------- eq. 2

Substitute equation 1 in equation 2:

$54 = 2(4y-3) + 2y\\54 = 8y - 6 + 2y\\54 + 6 = 8y + 2y\\60 = 10 y\\\\\frac{60}{10}= y\\y = 6$

Using the value of y, we find x.

$x = 4y - 3\\x = 4(6) -3\\x= 24 - 3\\x = 21$

4 0

4 years ago

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

6 0

3 years ago

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e.

zaharov [31]

Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:_Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________QuQuestion

Show that for a square Question Question

Show that for a square symmetric matrix M, Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________tric mQuestion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________atrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:___________estion

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:______________Question

Show that for a square symmetric matrix M, any two eigen-vectors v1, v2 with distinct eigen-values λ1, λ2, are orthogonal, i.e. inner product of v1 and v2 is zero. This shows that a symmetric matrix has orthonormal eigen-vectors:__________________

3 0

3 years ago