Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
Substitute each value of x in y=2x-3
so,
first box (-2)
y= 2(-2)-3
y= -4-3
y= -7
second box (0)
y= 2(0)-3
y= 0-3
y= -3
third box (3)
y=2(3)-3
y=6-3
y=3
Answer:
solution
Step-by-step explanation:
solution is the answer
Answer:
P = 2(n - 6) + 2(n^2 - 8)
Step-by-step explanation:
Remembering that Area = Length times Width, we factor the given function
A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:
A = n^3 - 6n^2 - 8n + 48 factors as follows:
A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)
We can label '(n - 6)' "width" and '(n^2 - 8'
length.
Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:
P = 2(n - 6) + 2(n^2 - 8)
Well when you see parentheses set up like these together that automatically means to multiply. The solution is:
<span>Apply the FOIL method: <span>(a+b)(c+d)=ac+ad+bc+bd</span>
</span><span><span>x2</span>+5x+3x+15</span>
<span>Simplify
</span><span><span><span>x2</span>+8x+15</span></span>
