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liubo4ka [24]
3 years ago
6

Hey guys marking brainliest What should I add in the background

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

Some flowers and some shading in it

MrMuchimi3 years ago
6 0

Answer:

GIVE IT A BACKGROUND OF CLOUDS AND MAKE THIS COLOURFULL IT WILL LOOK NICE..

You might be interested in
Cual es el decimal de 9/20
I am Lyosha [343]

Answer:

.45

Step-by-step explanation:

Para convertir 9/20 a decimal, simplemente divide 9 entre 20. No se preocupe. No necesita sacar la calculadora, porque lo hicimos por usted.

9/20 como decimal es: .45

7 0
3 years ago
Read 2 more answers
Please help! I need answers for both questions it’s very confusing!
Lilit [14]

Answer:

for number 5 its:

-15 -8 8/9 -3.3

and for number 6 its:

-3.3 -8 8/9 and -15

also sorry if its wrong

5 0
2 years ago
Read 2 more answers
A satelite is 5,400 miles from the horizon of earth. Earths radius is about 4000 miles. Find the approximate distance the sateli
kakasveta [241]

Answer:

The distance of Satelite from the earth's surface = 2720.12 miles

Step-by-step explanation:

Below is the calculation for distance:

Use Pythagorean theorem

Distance, d² = 5400² + 4000²

d² = 45160000

d = 6720.12

Subtract the radius to find the distance from earth's surface.

Distance = 6720.12 - 4000 = 2720.12

The distance of Satelite from the earth's surface = 2720.12 miles

5 0
3 years ago
What's the Answer to this problem?
MariettaO [177]
Depth = Volume / (length x width)
4 0
2 years ago
Stephon makes the following statements: statement 1 lim x -3 f(x) exists and is equal to 1 statement 2 lim x 1 f(x) exists and i
Mandarinka [93]

Neither statement 1, nor statement 2 are correct

The given Stephon's statements are;

Statement 1; \mathbf{\lim \limits  _{x \to -3} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to -3} f(x) = 1}

Statement 2; \mathbf{\lim \limits  _{x \to 1} f(x)}  \ \mathbf{Exist} \ and \mathbf{\lim \limits  _{x \to 1} f(x) = 1}

The analysis of the graph and reason for the answer

From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement

The limits of the domain and range of the graph includes;

\mathbf{\lim \limits  _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}

f(x) = Defined for -∞ ≤ x < -3

Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write

\mathbf{\lim \limits  _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}

From we above, we have that neither statement 1, nor statement 2 are correct

Learn more about open and closed circles on graph lines

brainly.com/question/8648835

4 0
3 years ago
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