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murzikaleks [220]
3 years ago
13

Please help!! 80 pts

Mathematics
2 answers:
zhenek [66]3 years ago
8 0

Simply you must separate this shape into 6 sections in the picture you have 6 shapes and each should be multiplied by length and width

12*25+ 12*18+18*25+12*18+18*25+12*25=1932

jonny [76]3 years ago
3 0

To solve this question, you have to take the 2D shape and divide it up into 6 boxes, of which you find the area of each. For easier reference, here's a picture where I've numbered the boxes.

Box 1: Nothing special here, just 25*12= 300 cm²

Box 2: The height of box 2 is obvious but the length is found from the above box. 25*18= 450 cm²

Box 3: Box 3 is the opposite of box 2, with an obvious length, but a width which is found from box 2. 12*18= 216 cm²

Box 4: Box 4 receives its height from box 2 and its length from box 6. 25*18= 450 cm²

Box 5: Box 5 has an obvious length but receives its height yet again from box 2. 12*18= 216 cm²

Box 6: Box 6's parameters are both obvious. 25*12= 300 cm²

The next step is to add the area of all the sections. 300+450+216+450+216+300= 1932 cm²

I hope this helped you!

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Hope this helps, have a wonderful day/night, stay safe, happy holidays, and merry christmas!

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When hired at a new job selling jewelry, you are given two pay options:
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Option a because you will make more orofits

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6 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
4 years ago
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