Solve for y. 3X+2y=12

A country is planning to decrease government spending in order to reduce the national debt. If the outlined changes are put into

SOVA2 [1]

Answer

Graph D represents the national debt of the country over the next years.

Solution-

The country's debt will decrease exponentially by one-third each year.

Current debt is $60 billion.

This problem can be treated as an exponential decay problem.

The general exponential decay function is,

$y=a(r)^{-x}$

Where,

a = initial value,

r = rate of change,

-ve sign of x represents the decrease in value of y as x increases.

Here, the rate of change is 3 as each year the debt becomes on third, and initial value of debt is $60, so

$y=60(3)^{-x}$

Plotting a graph taking number of year on x-axis and debt on y-axis, we can generate a graph for this function.

Putting different values of x, we can get the values of y. So the graph must have (0, 60), (1, 20), (2, 6.66), (3, 2.22), (4, 0.74), (5, 0.24) points on it.

Option B and C are incorrect, as they do not start from 60. (they don't have (0,60) on their curve)

Between option A and D, curve in D has all the points on it. So D is the correct graph.

5 0

3 years ago

Read 2 more answers

TRUE OR FALSE: F(x)=-3(x+2)(x-5)^3>0 when x<-2 or x>5 PLEASE HELP!!!!

Hitman42 [59]

F(x) = -3(x + 2)(x - 5)^3 > 0
(x + 2)(x - 5) > 0
x + 2 > 0 or x - 5 < 0
x > -2 or x < 5
-2 < x < 5

Therefore, the stated interval is false.

6 0

3 years ago

If x = 3 and y = -1, then 3x2 + 2xy - 5 = ? A: 18 B: 24 C: 12 D: 16

iris [78.8K]

$x = 3 , \ y = -1 \\ \\ 3x^2 + 2xy - 5 = 3\cdot 3^2 + 2\cdot 3\cdot (-1)-5=\\ \\=3\cdot 9 -6-5=27-11=16 \\ \\ Answer : \ D: \ \ 16$

8 0

3 years ago

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The average yield of the standard variety off soybeans per acre on a farm in a region is 48.8 bushels per acre, with a standard

I am Lyosha [343]

Answer:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

$p_v =P(Z>2.3)=1-P(Z$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

Step-by-step explanation:

1) Data given and notation

$\bar X=53.4$ represent the sample mean

$\sigma=12$ represent the population standard deviation assumed

$n=36$ sample size

$\mu_o =48.8$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 48.8, the system of hypothesis would be:

Null hypothesis: $\mu \leq 48$

Alternative hypothesis: $\mu > 48$

Since we assume that know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{53.4-48.8}{\frac{12}{\sqrt{36}}}=2.3$

4)P-value

Since is a right tailed test the p value would be:

$p_v =P(Z>2.3)=1-P(Z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean is not significantly higher than 48.8 at 1% of signficance.

3 0

3 years ago

Help asap will give brainliest

ArbitrLikvidat [17]

Answer:

• Equation = $2(\frac{7}{4}w + w) = 176$