Answer:
Solution given:
Volume of cone=⅓πr²h
Volume of cylinder=πr²h
1.
volume =πr²h=π*(10/2)²*6=<u>471.23mm³</u>
2.
Volume =πr²h=π*8*12.5=<u>314.16in³</u>
3.
volume =⅓πr²h=⅓*π*4²*3=<u>5</u><u>0</u><u>.</u><u>2</u><u>6</u><u>c</u><u>m</u><u>³</u>
4.
Volume =⅓πr²h=⅓*π*(8/2)²*12=<u>2</u><u>0</u><u>1</u><u>.</u><u>0</u><u>6</u><u>i</u><u>n</u><u>³</u>
The answer is 26
Explanation:
It’s easy
Isolate the variable x.
1-2x=-x-3
1=x-3
x=4
X/9=1
Multiply both sides by 9. So x=9.
Complete question :
It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
Answer:
0.929 ; 0.306
Step-by-step explanation:
Using the information:
P(stock) = P(s) = 28% = 0.28
P(fixed income) = P(f) = 0.85
P(stock and fixed income) = p(SnF) = 26%
a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.
P(F|S) = p(FnS) / p(s)
= 0.26 / 0.28
= 0.9285
= 0.929
(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
P(s|f) = p(SnF) / p(f)
P(S|F) = 0.26 / 0.85 = 0.3058823
P(S¦F) = 0.306 (to 3 decimal places)
