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ik im not first but have a lovely day! u are really kind! never forget that!
Answer:
Step-by-step explanation:
The window consists of a large square and 4 smaller triangles on the outside. The side length of this square is marked as 10, and therefore the area of this square is 
.
The area of a triangle is given by 
. Since the problem states that the overlapping squares are congruent, both legs of the triangle will be 
and intersect at a 
angle.
Thus, the sum of all four triangles is 
.
Therefore, the area of the window is:
Answer:
I think the answer is D. (2,6,8) because if the ones on the right are y - coordinates in the Function then it should be correct. If not sorry
(Range is y - coordinate)
(Domain is x - coordinate)
So there is an identity we'll need to use to solve this:
cos(x+y) = cosxcosy - sinxsiny
replace the numerator with the right hand side of that identity and we get:
(cosxcosy - sinxsiny)/cosxsiny
Separate the numerator into 2 fractions and we get:
cosxcosycosxsiny- sinxsiny/cosxsiny
the cosx's cancel on the left fraction, the siny's cancel on the right fraction and we're left with:
cosy/siny - sinx/cosx
which simplifies to:
coty - tanx
Answer:
x = 20
y = 10
m∡8 = 110°
Step-by-step explanation:
m∡1 + m∡2 = 180
5x + y + 3x + y = 180
8x + 2y = 180
m∡1 = m∡8 (they are alternate-exterior angles and are congruent)
5x + y = 3x + 5y
2x = 4y
x = 2y
Substitute '2y' for 'x' in 8x + 2y = 180
8(2y) + 2y = 180
18y = 180
y = 10
x = 2(10)
x = 20
m∡8 = 3(20) + 5(10) = 110°
