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andrew-mc [135]
3 years ago
15

Sam decided to lose weight and went on a diet. The figure below depicts a graph, showing how his weight changed during the year.

Using this graph, answer the following questions:
What was Sam’s weight at the beginning of the year?

Mathematics
2 answers:
Triss [41]3 years ago
8 0

Answer:

100kg

Step-by-step explanation:

because at the start of the diagram it's pointing at 100kg

elena-14-01-66 [18.8K]3 years ago
6 0

Answer:

100kg

Step-by-step explanation:

On the graph 100kg is where the line starts so that his weight when he started. Hope this made sense!

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mash [69]
Solving for the missing variable
6 0
3 years ago
Sarah used 2.5 cups of cheese in a dish that serves 10 people. Amy used 1.6 cups of cheese in a dish that serves 8 people. Who h
motikmotik

Answer:

Amy

Step-by-step explanation:

Find their amounts of cheese per serving by dividing the cups of cheese by the number of people:

Sarah:

2.5/10

= 0.25

Amy:

1.6/8

= 0.8

Since 0.8 is bigger than 0.25, Amy has more cheese per serving.

8 0
3 years ago
Read 2 more answers
Ethan was busying marshmallows for a family bonfire. Each bag of marshmallows was 250 g. If Ethan wanted to buy 3 kg of marshmal
sp2606 [1]
It's 12 bags (3000/250)
6 0
3 years ago
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The fuel tank of a certain airplane can hold up to 400 gallons of fuel. Let W be the total weight of the airplane (in pounds). L
Lady bird [3.3K]
A reasonable function is W = 7F + 5000


Where W is the weight of the plane and F is the number of gallons of fuel.


The domain is the set of possible values for F. That is from 0 (empty tank) to 400 (full tank).


So the domain is F = [0,400], or what is equivalente 0 ≤ F ≤ 400.


The range is the set of values of W.


The minimum value of W is when F = 0 => W = 7(0) + 5000 = 5,000.


The maximum value of W is when F = 400 => W = 7(400) + 5000 = 7,800 


So the range is W = [5,000 ; 7,800], pr 5000 ≤ W ≤ 7,800. 
7 0
3 years ago
Take a factor out of the square root:
klasskru [66]

Answer:

1.  |y| sqrt(10)

2.  |x| sqrt(x)

3. a^2 sqrt(a)

4.  4 |y|^3 sqrt(3)

5.  1/4 *|x| sqrt(3x)

Step-by-step explanation:

1.  sqrt(10y^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(y^2) sqrt(10)

|y| sqrt(10)

We take the absolute  value of y because -y*-y = y^2 and the principle square root is y

2.  sqrt(x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(x^2) sqrt(x)

|x| sqrt(x)

3. sqrt(a^5)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(a^4) sqrt(a)

a^2 sqrt(a)

4.  sqrt(16 y^7)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(16) sqrt(y^6)sqrt(y)

4 |y|^3 sqrt(3)

5.  sqrt(3/16x^3)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt(1/16) sqrt(x^2)sqrt(3x)

1/4 *|x| sqrt(3x)

8 0
3 years ago
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