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3 years ago

5y-2x=4(solve for y) solve step by step

Mathematics

1 answer:

Hoochie [10]3 years ago

4 0

Your answer will be y= 4/5

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AAAAAAA HELP ME PLZZZZ

Galina-37 [17]

Answer:

12 i believe

Step-by-step explanation:

volume; LxWxH

3x2x2

3x2=6

6x2=12

sorry if this is wrong lol but this is what i believe it is

6 0

3 years ago

Find a polynomial equation that has double zeros at x = -1, and x = 8.

blondinia [14]

Answer:

x^2-7x+8=0

Step-by-step explanation:

(x+1)(x-8)=0

x^2-7x+8=0

3 0

3 years ago

Read 2 more answers

DeMarco has the following coins in his pocket: 5 nickels, 3 dimes, and 2 quarters. What percent of one dollar does DeMarco have

Irina18 [472]

25% because 5 nickles equals 25 cents

7 0

3 years ago

Read 2 more answers

Absolute value of |x|= 5\6

12345 [234]

Hey there!☺

$Answer:\boxed{x=\frac{5}{6},-\frac{5}{6}}$

$Explanation:$

$|x|=\frac{5}{6}$

To solve for x, simplify both sides of the equation and then isolate the variable:

$|x|=\frac{5}{6}\\x=\frac{5}{6},-\frac{5}{6}$

Hope this helps!☺

4 0

4 years ago

Find a compact form for generating functions of the sequence 1, 8,27,... , k^3

pantera1 [17]

This sequence has generating function

$F(x)=\displaystyle\sum_{k\ge0}k^3x^k$

(if we include $k=0$ for a moment)

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k$

Take the derivative to get

$\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k$

$\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k$

Take the derivative again:

$\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k$

$\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k$

Take the derivative one more time:

$\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k$

$\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k$

so we have

$\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}$

5 0

3 years ago