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madam [21]
3 years ago
9

Sometimes, fourth-generation languages (4GLs) are called procedural languages

Computers and Technology
1 answer:
irakobra [83]3 years ago
7 0
Hi!

In 1981, the term 4GL was actually used to refer to languages which were <em>non-procedural. </em>A procedural language does not possess <em>object-oriented </em>capabilities. 4GL's often times have OOP properties, so I believe the answer to this question is going to be <em>false. </em>=)
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ira [324]

Answer:

Pluggable authentication modules (PAM).

Explanation:

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6 0
3 years ago
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vitfil [10]

Answer:

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4 0
2 years ago
4.5 Code Practice
dmitriy555 [2]

i = 0

while True:

   user_input = input("Please enter the next word: ")

   if user_input == "STOP":

       break

   i += 1

   print("#{}: You entered {}".format(i,user_input))

print("All done. {} words entered.".format(i))

First we set i equal to zero so that we can keep track of how many words we input.

We set while True so that its a continuous loop until a certain condition is met to break out of the loop.

user_input is set equal to whatever word the user enters.

our if statement tells us to break out of the while loop if the user inputs "STOP"

If the user does not enter STOP i is set equal to itself plus 1. This just means we add one to i for every new word entered.

Then we print whichever word is entered.

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7 0
3 years ago
A numeric literal that is written with a decimal point is called a ________. real number floating-point value decimal literal do
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6 0
2 years ago
Lists and Procedures Pseudocode Practice For each situation, provide a pseudocoded algorithm that would accomplish the task. Mak
Andrei [34K]

Answer:

The pseudocoded algorithm is as follows:

Procedure sumOdd(lotsOfNumbers):

    oddSum = 0

    len = length(lotsOfNumbers)

    for i = 0 to len - 1

         if lotsOfNumbers[i] Mod 2 != 0:

              OddSum = OddSum + lotsOfNumbers[i]

Print(OddSum)

Explanation:

This defines the procedure

Procedure sumOdd(lotsOfNumbers):

This initializes the oddSum to 0

    oddSum = 0

This calculates the length of the list

    len = length(lotsOfNumbers)

This iterates through the list

    for i = 0 to len-1

This checks if current list item is odd

         if lotsOfNumbers[i] Mod 2 != 0:

If yes, the number is added to OddSum

              OddSum = OddSum + lotsOfNumbers[i]

This prints the calculated sum

Print(OddSum)

6 0
3 years ago
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