Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
Answer: yes
Step-by-step explanation:
Simply just yes
Answer:
3x + 21
Step-by-step explanation:
(3)(x+7)
Now, we distribute the 3 in each term of (x+7)
So, 3*x = 3x and 3*7 = 21.
So our resulting term would be 3x+21.
The answer is d as in dog
Answer: 0.9
Step-by-step explanation:
