Question

The circle below is centered at the point (3, 1) and has a radius of length 2.

Answer 1

Answer:

$x^2 + y^2 - 3x -y +6 = 0$

Step-by-step explanation:

The equation of a circle with center $(h,k)$ and radius $r$ is given by

                 $(x - h)^2 + (y - k)^2 = r^2$

Here the center is: $(3,1)$ and radius is $2$.

Therefore, we have:

$(x - 3)^2 + (y - 1)^2 = 2^2$

$\implies x^2 -3x +9 +y^2 -y +1 = 4$

$\implies x^2 + y^2 -3x -y +6 = 0$

Answer 2

Answer:

Step-by-step explanation:

an equation of the circle Center at the w(a,b) and ridus : r is :

(x-a)² +(y-b)² = r²

in this exercice : r = 2 and  a =3   b =1

so : (x-3)² +(y-1)² = 2²