Answer:
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
Step-by-step explanation:
Total number of possible ways to choose 2 components for defectives out of 4 components = 4C2 = 6
Y can only take values of 2, 3 and 4
So, Probability of Y = P(Y) = 1C(Y-1) / 6
when Y = 2, P(2) = 1/6 = 0.167
when Y = 3, P(3) = 2/6 = 0.333
when Y = 4, P(4) = 3/6 = 0.5
