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Llana [10]
3 years ago
11

Please help me for this question

Mathematics
2 answers:
lesya [120]3 years ago
7 0
The perimeter is 58 yards..........
Artist 52 [7]3 years ago
6 0
7+14+15+5+8 + 9 =58 yard

answer 58 yd

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exis [7]
The answer to this is 3:4
6 0
3 years ago
Read 2 more answers
Please help out thanks :) ​
Mkey [24]
The correct answer is D The last one


Step by step is below

Hopefully this help you


Have a great day :)

3 0
3 years ago
Please help I need to turn this in today.
Bogdan [553]

Answer:

C

Step-by-step explanation:

If you have a Ti-84 series calculator, press "stat" then "Edit..." and then fill in the data table values for x and y in two lists. Then press "2nd" and "mode" to quit. Now press "stat" again and right arrow over to "calc" and press down until you find "ExpReg" and set the "Xlist" and "Ylist" that you used and you will get C as the answer. Another way to do this is to manually substitute values into all 4 equations, which is boring.

8 0
1 year ago
If the perimeter of vectangle wall is 360 cm and its breath is 60cm. Find its length and also find the totalt cost of painting t
alexdok [17]

Answer:

<u>Rs. 72</u>

Step-by-step explanation:

We have 2 values here,

  • Perimeter of the rectangle = 360 cm
  • Breadth of the rectangle (b) = 60 cm.

Firstly, we must find the length of the rectangle (l).

So, according to the formula,

Perimeter = 2 (b + l)

360 = 2 (60 + l)

360 = 120 + 2l

360 - 120 = 2l

240 = 2l

120 cm = l

Now, we need to find the area of the rectangular wall & then convert it from cm² to m² as the cost of painting is given in m².

So,

Area = lb

Area = 120 × 60

Area = 7,200 cm²

Let's convert it to m² now,

7200/1000

= 7.2 m²

Given, cost of painting per m² = Rs. 10

So, the cost of painting the wall is,

10 × 7.2

= <u>Rs. 72</u>

<u>________________________________</u>

Hope it helps!

\mathfrak{Lucazz}

3 0
2 years ago
Solve this equation for x. Round your answer to the nearest hundredth. 0.77 = log x​
Alekssandra [29.7K]

Answer:

x ≈ 5.89

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra II</u>

  • Exponential to Logarithmic:                                                                             \displaystyle b^m=x \rightarrow log_bx=m

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

0.77 = log(x)

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Equality Property] Raise both sides to the 10th power:                                \displaysytle 10^{0.77} = 10^{logx}
  2. Simplify:                                                                                                             \displaysytle x = 10^{0.77}
  3. Evaluate:                                                                                                           \displaysytle x = 5.88844
8 0
3 years ago
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