Question

Construct the triangle dce using as coordinates of its vertices points d(−4, 0), c(0, −2), and e(5,3). Find the coordinates of intersection of side ce with the x-axis.

Answer 1

Answer:

So, coordinate of intersection point  = (2,0)

Explanation:

Given a triangle DCE whose coordinate of the vertex are :

D(−4, 0), C(0, −2), and E(5,3)

We will find the equation of CE

Firstly find the slope of CE

Slope (m) = $\frac{y_{2} - y_{1} }{x_{2} - x_{1}}$

m = $\frac{3-(-2)}{5-0}$ = 1

Equation of line is :

y - y₁ = m(x - x₁)

y - (-2) = 1(x-0)

y + 2 = x                   equation of CE

Find the intersection point of CE and x-axis

Put y = 0 to find the x-intercept

0 + 2 = x

x = 2

So, coordinate of intersection point  = (2,0)