Answer:
Answer D is correct
Step-by-step explanation:
<em>Twice</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>number</em><em> </em><em>is</em><em> </em><em>5</em><em>8</em>
<em>
</em>
<em>Four</em><em> </em><em>times</em><em> </em><em>that</em><em> </em><em>number</em><em> </em><em>will</em><em> </em><em>be</em>
<em>
</em>
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<span>2+2(2+2*0)2+0
</span><span><span>2+2×(2+0)×2+0
</span><span><span>2+2×2×2+0
</span><span><span>2+8+0</span><span>
10
</span></span></span></span><span>---------------------
</span>
Assuming you mean y = 200 - 16t^2, we have all the required information needed to solve this problem. The y-value is the height of the building and the t-value represents the number of seconds after the shoe fell off.
Since we are trying to solve <em>for t</em>, we will be using our y-value. The problem states that we landed on a building with a height of 31 feet. We can plug this into the y-value, since that is what y is defined as (the height of the building).
Now we have:
31 = 200 - 16t^2
We can solve this to find t:
-169 = -16t^2
169 = 16t^2
10.5625 = t^2
3.25, -3.25 = t
We have found two answers for t. However, the negative value is not a solution because we can not have a negative number of seconds. Thus, 3.25 is the only value of t which works for this problem.
Since t is the value we are trying to find, we have our answer. The shoe hits the building after 3.25 seconds.
Answer:
30
Step-by-step explanation:
i promise this is the answer i go to k12 and got the answer correct
