The immense amount of information stored in DNA is coded with just four base nucleotides. These four nucleotides are paired by twos to form <u>complementary </u>DNA chains.
The makeup of DNA is limited to two <u>pairs </u>of nucleotides bases. One of these pairs is a pyrimidine base whilst the other forms a purine base. The four nucleotides that will make up the entire DNA code are:
- Adenine (A)
- Guanine (G)
- Cytosine (C)
- Thymine (T).
A and G will pair to form the purine base, meanwhile, Cytosine pairs with Thymine to form the <em>pyrimidine base</em>. As per the entire DNA code, A will always pair with G.
Whilst C always pairs with T. This is due to the very nature of the nucleotides themselves and will not change throughout the synthesis or duplication of DNA. Therefore, to complete the complementary strand described in the assignment we must match the letter given with its corresponding base pair, using this rule of DNA.
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Answer:
I think it is B. Market Penetration strategy.
Explanation:
I'm very sorry if this is wrong but studying the two possible answer (A or B)
B seemed the most probable due to the definition of the Market Penetration Strategy. Which is essentially "To focus on current products and current markets in order to increase market share". (I hope I was able to help! :)
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
