Answer:
0.5 m/s2
Explanation:
Step 1:
Data obtained from the question.
Total Mass = 60Kg
Net force = 30N
Acceleration =?
Step 2
Determination of the acceleration.
Force = Mass x Acceleration.
With the above equation, we can easily obtain the acceleration as follow:
30 = 60 x Acceleration
Divide both side by 60
Acceleration = 30/60
Acceleration = 0.5 m/s2
Now, we can thus say that the acceleration at that moment is 0.5 m/s2
This reaction, known as nuclear fusion, converts hydrogen atoms into helium. The by-product of nuclear fusion in theSun's core is a massive volume ofenergy that gets released and radiates outward toward the surface of the Sunand then into the solar system beyond it.
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Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Answer:
4.662 slugs
Explanation:
Your mass on the moon should always be the same as any planet you are on (due to law of mass conservation), only your weight be different as gravitational acceleration is different on each planet.
If you weight 150 lbf on Earth, and gravitational acceleration on Earth is 32.174 ft/s2. The your mass on Earth is
m = W / g = 150 / 32.174 = 4.662 slugs
which is also your mass on the moon.
Answer:
A. The time it takes the projectile to reach the top of its path is about 1 second.
Explanation:
Hi there!
The equation of the velocity of a projectile fired straight up is the following:
v = v0 + g · t
Where:
v = velocity of the projectile.
v0 = initial velocity.
g = acceleration due to gravity (≅ -9.8 m/s² considering the upward direction as positive)
t = time.
When the projectile reaches the top of its path, its velocity is zero, then, using the equation of velocity, we can solve it for the time:
v = v0 + g · t
0 = 10 m/s - 9.8 m/s² · t
t = -10 m/s / -9.8 m/s²
t = 1.0 s
The time it takes the projectile to reach the top of its path is about 1 second.
