Answer:
534 ft
Explanation:
given,
speed of the vehicle = 60 mph
1 mph = 0.447 m/s
60 mph = 60 x 0.447 = 26.82 m/s
stopping distance = ?
Stopping distance of the car is equal to the distance traveled in the reaction time and the braking distance.
Reaction time of a common person = 1.5 s
taking coefficient of friction of the road = 0.3
using equation of stopping sight distance
S.D = RD + BD
RD is Reaction distance
RD = v t_r
RD = 26.82 x 1.5
RD = 40.23 m
BD is the braking distance
BD = 122.33 m
Stopping sight distance
SD = 40.23 + 122.33
SD = 162.56 m
1 m = 3.28 ft
162.56 m = 162.56 x 3.28
= 533.20 ft ≈ 534 ft
hence, the stopping distance will be equal to 534 ft
displacement and velocity
if drppoed then locally path vertical down ... towards centre of earth
Answer:
(C)Direct kick
Explanation:
In a game of soccer (foot-ball) there are lots of rules involved in the game and there is penalty for each of the rules violated. Some of the rules include penalty kick, free kick, throw in, goal kick etc.
Free kick is of two types; direct kick and indirect kick.
Direct kick is awarded when a player outside 18 yards box violently or dangerously charges a opponent.
Indirect kick can be awarded when a goalkeeper inside 18 yards box commits certain offenses.
Therefore, the correction option is (C)Direct kick
Answer:
a) 83.33 rad/s^2
b) 2500 rad/s
c) 6187.5 rad
Explanation:
Given data:
radius of wheel = 20.0 cm
mass of wheel = 3.0 kg
force = 25 N
a) angular acceleration
we know torque is given as
solving for angular acceleration 
b) angular velocity
duartion of force applied = 30.0 sec
= o + 83.33 *30 = 2500 rad/sec
c) angular displacement
