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4 years ago

15

What is the area of a rectangle with vertices at (2, 3), (7, 3), (7, 10), and (2, 10)?

1 answer:

Ainat [17]4 years ago

7 0

Given:
x   y
2   3
7   3
7 10
2 10

It is easier to graph these vertices to avoid confusion.

Length: basis is the y-values : 10 - 3 = 7 units
Width: basis is the x-values: 7-2 = 5 units

Area = Length * Width
A = 7 units * 5 units
A = 35 units² Choice D.

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2 years ago

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3 years ago

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3 years ago

Please Help! Math help Needed

Sholpan [36]

ANSWER

The exact value is 24√3

The approximate value is 41.6 to the nearest tenth.

x=52.1 units.

EXPLANATION

Let the blue dotted line be h units.

This line is opposite to the 60° angle.

The side length of the triangle which is 24 units is adjacent to the 60° angle.

So we use the tangent ratio,

$\tan(60 \degree) = \frac{opposite}{adjacent}$

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This is that approximate value to the nearest tenth.

To find the side length , x, we need to use the second triangle.

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3 years ago