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NemiM [27]
3 years ago
8

If you were to roll the dice one time what is the probability it will NOT land on a 2? Put your answer in fraction form.

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer:

5/6

Step-by-step explanation:

On a standard 6-sided die, there is only one 2. That means that there are 5 other numbers that it could land on (1, 3, 4, 5, 6).

Using that information, the probability of it not landing on a 2 is 5 out of 6 or 5/6. This is because you must do part over whole. The "part" in this situation is the 5 "wanted" numbers, and the "whole" is 6 because there are six potential numbers that it could land on.

I hope this helps.

tensa zangetsu [6.8K]3 years ago
8 0

Answer: 5/6

There is only one side with two and a total of six sided therefore 6-1=5 so 5/6

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4 0
3 years ago
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Quadrilateral KMPT is dilated by a scale factor of 3/4 to create K'M'P'T'. The perimeter of quadrilateral KMPT is x units. What
777dan777 [17]

Answer:

B) \frac{3}{4} x units

Step-by-step explanation:

Let quadrilateral KMPT be a rectangle with dimensions 12 units by 8 units. Then its perimeter would be equal to:

Perimeter of a rectangle = 2 (l + b)

where: l is the length = 12 units and b is the breadth = 8 units. So that:

Perimeter of KMPT = 2 (12 + 8)

                               = 40 units

Dilating KMPT by a scale factor of \frac{3}{4} would create K'M'P'T' of dimensions; \frac{3}{4} × 12 units by \frac{3}{4} × 8 units. Thus, the dimensions of K'M'P'T' would be 9 units by 6 units.

Perimeter of K'M'P'T' = 2 (l + b)

                                  = 2(9 + 6)

                                  = 30 units

Comparing the perimeters of KMPT and K'M'P'T', the perimeter of K'M'P'T' would be  \frac{3}{4} × perimeter of KMPT.

Therefore, if the perimeter of KMPT is x units, then;

         perimeter of K'M'P'T' = \frac{3}{4} * x units

                                            = \frac{3}{4}x units

6 0
3 years ago
Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia
Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 75, \sigma = 12.5

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 75}{12.5}

Z = 0.48

Z = 0.48 has a pvalue of 0.6844

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 75}{12.5}

Z = -0.48

Z = -0.48 has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

3 0
3 years ago
Read 2 more answers
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