Answer:
The probability that Jason will get exactly 7 strikes out of 10 attempts is 0.117.
Step-by-step explanation:
We are given that Jason is a very good bowler and has proven over the course of a season of league play that he gets a STRIKE 50% of the time.
Also, Jason has been given 10 attempts.
The above situation can be represented through binomial distribution;
where, n = number trials (samples) taken = 10 attempts
r = number of success = 7 strikes
p = probability of success which in our question is % of the time
he gets a strike, i.e; p = 50%
<em><u>Let X = Number of strikes Jason get</u></em>
So, X ~ Binom(n = 10, p = 0.50)
Now, probability that Jason will get exactly 7 strikes out of 10 attempts is given by = P(X = 7)
P(X = 7) =
=
=
= <u>0.117</u>
Therefore, the probability that Jason will get exactly 7 strikes out of 10 attempts is 0.117.