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andrew-mc [135]
3 years ago
6

Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac

hers per college has an average μ = 150 and a standard deviation σ = 20.
a. Use Chebyshev's Rule to make a statement about the minimum percentage of colleges that have between 90 and 210 teachers. (Round your answer to two decimal places if necessary.)

(b) Assume that the population is mound-shaped symmetrical. What proportion of colleges have less than 170 teachers?
Mathematics
1 answer:
agasfer [191]3 years ago
8 0

Answer:

a) \frac{8}{9} =0.89

b) 0.8413

Step-by-step explanation:

we know that

P(║ x -\mu║ \leq  k\sigma) \geq 1 -\frac{1}{k^2}

so, \mu = 150, \sigma = 20

k =  \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3

P(║ x -150 ║ \leq  3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}

x - N(150, 20^2)

P(X \leq 170) = 0.8413447

check

P norm = \frac{170 - 150}{20}= 0.8413447

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