Question

Please help!!

Answer 1

Your answer would be D. The angle C is 47 degrees.

Answer 2

From the given picture, we see that two sides and one angle is given

Using them we have to find the value of angle C

side AB=c=14 in

side BC=a=18 in

angle A= 110 degree

Now plug these values into sine formula

$\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}$

or $\frac{18}{\sin(110)}=\frac{b}{\sin(B)}=\frac{14}{\sin(C)}$

or $\frac{18}{\sin(110)} =\frac{14}{\sin(C)}$

or $\frac{18}{0.93969262} =\frac{14}{\sin(C)}$

or $19.1551999206=\frac{14}{\sin(C)}$

or $\sin(C)=\frac{14}{19.1551999206}$

or $\sin(C)=0.730872037777$

or $C=\sin^{-1} (0.730872037777}$

C=46.959549954213535880191108778655

Which is approx 47 degree.

Hence final answer is C=47 degree.