1. y = 2/3x - 5
2. 4x - 6y = 30
Divide 2. by 2
3. 2x - 3y = 15
Substitute 1. into 3.
4. 2x - 3(2/3x - 5) = 15
5. 2x - 2x + 15 = 15
6. 15 = 15
False. There are an infinite number of solutions.
Answer:
Step-by-step explanation:
Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.
We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.
I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.
The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.
Answer:
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Answer:
It took Markus half an hour to drive home from work. He averaged 34 miles per hour. How far does Markus live from his work?
Solution
We are given that it takes 1/2 an hour for the trip. This is a time:
t = 1/2
We are given that he averages 34 miles per hour. This is a rate:
r = 34
We are asked how few he has traveled. This is a distance. We use the d=rt equation:
d = rt
= (34)(1/2)
= 17
Markus lives 17 miles from work.
Now try one by yourself. If you want to see the answer, put your mouse on the yellow rectangle and the answer will appear.
Exercise 1
The current along the beach is moving towards the south at 1.5 miles per hour. If a piece of debris is placed into the water, how far will the current take it in 6 hours?
Step-by-step explanation: