You need to combine like terms.
it should be:
12ibs-7ibs-5oz-10z
5ibs-(-5oz)
2x-9= (-7^2)
2x-9=49
2×=49+9
2x=58
x=58/2
x=29
Given that the height of the disc is modeled by the function:
h=-16t^2+20t+6
a] The maximum height will be as follows:
At maximum height:
h'(t)=0
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus the maximum height will be:
h(5/8)=-16(5/8)^2+20(5/8)+6
=12.25 ft
b] <span>How long will it take the disc to reach the maximum height?
</span>time taken to reach maximum height will be:
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus time taken to reach maximum height is t=5/8 sec
c]<span>How long does it take for the disc to be caught 3 feet off the ground?
</span>h(t)=-16t^2+20t+6
but
h(t)=3
thus
3=-16t^2+20t+6
solving for t we get:
0=-16t^2+20t+3
factoring the above we get:
t=5/8-/+√37/8
t=-1.5256 or 2.776
since there is no negative time we pick t=2.776
Hence time taken for the disc to be caught 3 ft from the ground is 2.776 ft
Cows - sheep = 19
Ducks - hens = 19
Unless there is more data, that is all you can do.
The shapes found in the image are incomplete circle and triangle.
The radius is given at 35 yards.
Area of the circle = 3.14 * (35yd)² = 3.14 * 1225 yd² = 3,846.5 yd²
Area of the circle = 3,846.50 yd² * (280/360)° = 2991.72 yd²
<span>The area of the triangular section will be </span>
<span>Area of the triangle = (1/2)*(45 yd)*(25 yd) = 562.5 yd</span>²<span>
</span>
<span>So the total area is </span>
<span>(2991.72 + 562.5) yd</span>²<span> = 3554.22 yd^2 ≈ 3554 yd</span>² Choice D.
