Both 2 and 6 are divisible by 2, so you would divide them by 2 and your fraction would be reduced to 1/3. You would get that answer by simply reducing the fraction.
Answer:
its a thrapizium.so you can find the area like this....
Answer:
x^3+2x^2-x-2=(x+2)(x-1)(x+1)
The other two factors are x-1 and x+1
Step-by-step explanation:
Use synthetic division:
x^3+2x^2-x-2 / x+2
-2 | 1 2 -1 -2
-2 0 2
_________
1 0 -1 0
This means x^2-1 with no remainder, but we can still break it down. The factors of -1 are 1 and -1, so we must find the factors:
1 | 1 0 -1
1 1
______
1 1 0
This means x+1 so that's one factor
-1 | 1 0 -1
-1 1
_______
1 -1 0
This means x-1 so that's the other factor
Thus, the factors of x^3+2x^2-x-2 are (x+2)(x+1)(x-1)
It’s 3 because it just is okay math is hard
