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sergey [27]
3 years ago
15

What is the distance between the points (- 5, - 4) and (3, - 3) on a coordinate plane? Help asappp

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
7 0

Answer:

The distance between (-5, -4) and (3 , -3) is I think 9

Step-by-step explanation:

Hope this helps

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Paul has an eight-year loan with a principal of $26,900. The loan has an interest rate of 8.18%, compounded quarterly. If Paul p
babymother [125]

Answer:

The answer is "option b"

Step-by-step explanation:

Amount = $26,900

r= 0.0818 %

i=\frac{r}{4}\\\\

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t= 8 years

n= 8 \times 4

  =32

D=\frac{1-(1+i)^{-n}}{i}\\

   =\frac{1-(1+0.02045)^{-32}}{0.02045}\\\\=\frac{1-(1.02045)^{-32}}{0.02045}\\\\=\frac{1-0.52319627}{0.02045}\\\\=\frac{0.47680373}{0.02045}\\\\=23.3155858

Q= \frac{Amount}{Discount \ factor }\\

   =\frac{26900}{23.3155858} \\\\=1153.73468

Payment =1153.73468 \times  32\\\\

               = \$ 36919.5098\\

\text{Total interest = Payment - amount}

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\text{Finance charge = Total interest + service charge}

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3 0
3 years ago
A teacher has 3 hours to grade all the papers submitted by the 35 students in her class. She gets through the first 5 papers in
Andreyy89
So, she has 3hrs to grade all papers, for 35 students.. alrite.

the first 5, she does them in 30minutes.. what's the speed rate? well, 5/30 or 1/6

now, she has still 2 hours and a half, or 150 minutes, to do the remaining 30 papers... she has to work at a rate of 30/150 then... which is 1/5 simplified.

now if we take 1/6 as the 100%, what is 1/5 in percentage then?

\bf \begin{array}{ccllll}
rate&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{6}&100\\\\
\frac{1}{5}&x
\end{array}\implies \cfrac{\frac{1}{6}}{\frac{1}{5}}=\cfrac{100}{x}\implies \cfrac{1}{6}\cdot \cfrac{5}{1}=\cfrac{100}{x}\implies \cfrac{5}{6}=\cfrac{100}{x}
\\\\\\
x=\cfrac{6\cdot 100}{5}\implies x=120

so 1/5 is 120% in relation to 1/6... meaning the rate of 1/5 she needs to move through, namely 1 paper every 5 minutes, is 20% faster than 1/6.
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