The only safe conclusion is that point G lies on line FH or that point G lies somewhere between line FH. We cannot conclude that point G is the midpoint of line FH eventhough by virtue of definition of midpoint, the given equation is a proof equation. If G were to be midpoint, segment FG must be equal to segment GH in line FH.
Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:

A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so 
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:

0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Group 1: Group 2
1 : 3
Total amount of splits = 1 + 3 = 4
48/4 = 12
12 : 12+12+12
12 : 36
12 in pile 1 and 36 in pile 2.
(3,7),(-3,-5)
that’s what it would look like on a graph
Ok nice answer…… well done