Answer:
gv hjbiuhkjbOn the vertical axis, place frequencies. Label this axis "Frequency".
On the horizontal axis, place the lower value of each interval. ...
Draw a bar extending from the lower value of each interval to the lower value of the next interval.
Step-by-step explanation:
Answer:
Distance between school and home = 105 miles.
Step-by-step explanation:
Let distance = D miles
Time to take walking/jogging, t1 = D/6 hours
Time by car, t2 = D/35 hours
Average time, t
= (t1+t2)/2
= D(1/6+1/35)
= (D/210)(35+6)
=41D/210 hours
Given t = t1-3 hours
41D/210 - D/6 = 3
Solve for D
41D/210 - 35D/210 = 3
(41-35)D/210 = 3
6D/210 = 3
D = 3*210/6 = 105 miles.
(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)
Answer:
Kelvin’s error is that when he got the final result, that was the amount that was marked down. He still needed to find the price after the original price was marked down by that number wich in this case is $18.39. So using one of his steps, 30.65(0.6)=18.39. We can subtract 30.65 (original price) and 18.39 (mark down price). You’d get 11.26 dollars as the final price.
Cindy: 4mph
Taylin: 4m/30 min : 8 mph
Judy:5.5m/45min : 7mph
