Answer:first one
hope this helps
Answer:
Options (1), (3), (5) and (6)
Step-by-step explanation:
Option (1)
Both the circles M and H are same in shape. Therefore, both are similar.
True
Option (2)
MH = MS = [Radii of a circle]
MH = MO + OH
MH = ME + OH [Since, MO = ME]
MH = 10 + 25 = 35 cm
Area of circle M = πr²
= π(35)²
= 1225π
Area of circle H = π(25)²
= 625π
Area of M = 1.96(Area of H)
False
Option 3
OH + MS = 25 + 35
= 60 cm
True
Option 4
m∠HMS = 90°
Can't be figured out with the given informations
False
Option 5
Diameter of circle H = 2(radius)
= 2(25)
= 50 cm
True
Option 6
Circumference of circle S = 2πr
= 2π(ES)
Circumference of circle M = 2π(MS)
Ratio of the circumference of circle S and M = 
= 
True.
Options (1), (3), (5) and (6) are correct.
Answer:
The quotient is 3x - 11 + 60/(x + 5) ⇒ 2nd answer
Step-by-step explanation:
* We will use the long division to solve the problem
- The dividend is 3x² + 4x + 5
- The divisor is x + 5
- The quotient is the answer of the division
- If the divisor not a factor of a dividend, the quotient has
a remainder
* Lets solve the problem
- At first divide the first term in the dividend by the first term in
the divisor
∵ 3x² ÷ x = 3x
- Multiply the divisor by 3x
∴ 3x (x + 5) = 3x² + 15x
-Subtract this expression from the dividend
∴ 3x² + 4x + 5 - (3x² + 15x) = 3x² + 4x + 5 - 3x² - 15x = -11x + 5
- Divide the first term -11x in the new dividend by the first
term x in the divisor
∴ -11x ÷ x = -11
- Multiply the divisor by -11
∴ -11(x + 5) = -11x - 55
-Subtract this expression from the new dividend
∴ -11x + 5 - (-11x - 55) = -11x + 5 + 11x + 55 = 60
∴ The quotient is 3x - 11 with remainder = 60
* The quotient is 3x - 11 + 60/(x + 5)
2. C
Slope = 40/8 = 5
Slope of graph c = 5/1 = 5
3. D
Slope = 9/3 = 3
Slope of graph d = 81/27 = 3
The new y-intercept would be A)-1 because of the 4-5 = -1
