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3 years ago

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Pythagorean Theorem in Cones. I need a lot of help.

1 answer:

Nadya [2.5K]3 years ago

3 0

The Pythagorean Theorem formula is listed below. It can only be applied to right triangles.

(side1)^2 + (side2)^2 = (hypotenuse)^2

Since we are given that the base is 8cm, we know that the side of one triangle is 4cm. We are also given that the hypotenuse is 8cm. The height of the cone will be one of the short sides. If we plug these numbers into the formula, we get the following...

4^2 + height^2 = 8^2

If we solve for height, we get the following...

height = sqrt(8^2 - 4^2) = sqrt(64 - 16) = sqrt(48)

Since we are only asked for what is inside the square root, our answer is 48.

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L is the midpoint of KM. If KL = 14x and KM = 26x + 14, what is KL? Simplify your answer and write it as a proper fraction, mixe

NNADVOKAT [17]

Answer:

Step-by-step explanation:

L is the midpoint of KM. So, length of KL = length of LM

KL = LM = 14x

KL + LM = KM

14x + 14x = 26x + 14 {add the like terms}

28x = 26x + 14 {subtract 26x form both sides}

28x - 26x = 14

2x = 14 {divide both side by 2}

2x/2 = 14/2

x = 7

KL = 14x = 14*7

KL = 98

4 0

3 years ago

Determine the vertex of the function f(x) = 2(x − 5)2 + 8.

choli [55]

Answer:

Vertex ( 5 ,8) .

Step-by-step explanation:

Given : f(x) = 2(x − 5)² + 8.

To find : Determine the vertex of the function .

Solution : We have given

f(x) = 2(x − 5)² + 8.

Vertex form of parabola : f (x) = a(x - h)² + k, where (h, k) is the vertex.

On comparing f(x) = 2(x − 5)² + 8. with vertex form of parabola.

a = 2 , h = 5 , k = 8 .

Vertex ( 5 ,8) .

Therefore, Vertex ( 5 ,8) .

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Cbold%7B%5Cunderline%7B%5Cunderline%7BQuestion%3A%7D%7D%7D%7D" id="TexForm

Ronch [10]

Answer:

<h2> </h2><h2> ${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$ </h2>

Step-by-step explanation:

<h3><em><u>Question</u></em><em><u>:</u></em><em><u>-</u></em></h3>

To find the Binomial theorem form of $\bold{(4t-3)^{5}}$

<h3><em><u>As</u></em><em><u> </u></em><em><u>we</u></em><em><u> </u></em><em><u>know</u></em><em><u>:</u></em><em><u>-</u></em></h3>

<em>As</em><em> </em><em>in</em><em> </em><em>Bin</em><em>omial</em><em> </em><em>theorem</em><em> </em><em>:</em><em>-</em>

${(x - y)}^{5} = {x}^{5} - 5 {x}^{4} y + 10 {x}^{3} {y}^{2} - 10 {x}^{2} {y}^{3} + 5x {y}^{4} - {y}^{5}$

<h3><em><u>Solution</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em></h3>

$= {(4t - 3)}^{5}$

<em>Hence</em><em>,</em><em> </em><em>on</em><em> </em><em>using</em><em> </em><em>the</em><em> </em><em>Binomial</em><em> </em><em>theorem</em><em>,</em><em> </em>

$= {(4t)}^{5} - 5 {(4t)}^{4} (3)+ 10 {(4t)}^{3} {(3)}^{2} - 10 {(4t)}^{2} {(3)}^{3} + 5(4t) {(3)}^{4} - {(3)}^{5}$

<em>On</em><em> </em><em>formatting</em><em> </em>

$= {1024t}^{5} - 5 ({256t}^{4} )(3)+ 10 ({64t}^{3} ) (9 ) - 10 ({16t}^{2} )(27) + 5(4t) (81) - 243$

<em>On</em><em> </em><em>further</em><em> </em><em>formatting</em><em>.</em><em> </em>

$= {1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>required</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em>

${1024t}^{5} - 3840{t}^{4} + 5760{t}^{3} - 4320{t}^{2} + 1620t- 243$

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2 years ago

High school Geometry

xxTIMURxx [149]

Answer:

the answer is b. sss is not possible

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2 years ago

N+4=12 .step by step working please

liubo4ka [24]

Answer:

n+4=12

n=12-4

n=8

Step-by-step explanation:

hope it helps

3 0

3 years ago

Read 2 more answers