What is the sum of the first 10 terms in the geometric sequence -3 6 -12 24 -48

1 answer:

3 0

Use the formula for the sum of a geometric sequence:
Sum = (a(r^n - 1))/(r - 1)
where a is the first term, -3
r is the common ratio, -2
and n is the number of terms

Thus,
Sum = ((-3)((-2)^10 - 1))/(-2-1) = 1023

You might be interested in

Ona took a random sample of 20 soccer teams across Europe. She tracked the average number of goals

anygoal [31]

The predicted number of wins for a team that averages 1.5 goals per game will be 17 according to the regression model.

From the table given, the linear regression model for the data can be expressed as :

y = 14.02x - 3.64 ; where ;
y = Predicted number of wins ;
x = average number of goals per match ;
slope = 14.02 ;
Intercept = - 3.64

<u>The Number of wins for a team which averages 1.5 goals per match can be calculated thus</u> :

Average goals per match, x = 1.5

Substitute x = 1.5 into the equation :

y = 14.02(1.5) - 3.64

y = 17.39

y = 17 (nearest whole number)

Learn more :brainly.com/question/18405415

8 0

2 years ago

Please HELP! I DON'T KNOW HOW CAN I SOLVE THIS

Wewaii [24]

Answer:

Step-by-step explanation:

The Pythagorean Theorem:

$leg^2+leg^2=hypotenuse^2\to a^2+b^2=c^2$

$41.\\\\a=1,\ b=1,\ c=x\\\\x^2=1^2+1^2\\\\x^2=1+1\\\\x^2=2\to x=\sqrt2$

$42.\\a=1, b=2,\ c=x\\\\x^2=1^2+2^2\\\\x^2=1+4\\\\x^2=5\to x=\sqrt5$

$43.\\a=3,\ b=x,\ c=5\\\\3^2+x^2=5^2\\\\9+x^2=25\qquad\text{subtract 9 from both sides}\\\\x^2=16\to x=\sqrt{16}\to x=4$

$44.\\\\a=4,\ b=x,\ c=8\\\\4^2+x^2=8^2\\\\16+x^2=64\qquad\text{subtract 16 from both sides}\\\\x^2=48\to x=\sqrt{48}\\\\x=\sqrt{16\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x=\sqrt{16}\cdot\sqrt3\\\\x=4\sqrt3$