X = mia's score
eric scored 10 more then mia....so eric's score is x + 10
isabella scored 16 less then twice mia's score...so isabells's score is 2x - 16
so the expression x + x + 10 + 2x - 16 is a total of all 3 people's scores combined
The lowest percentage increase in the cost of dye that would make the scarves unprofitable is 42%
<h3>How to calculate the percentage?</h3>
(Price- Unit Cost)/Price= 20% or 0.2
Price- Unit Cost= 0.2 Price
0.8 Price = Unit Cost
Let Unit Cost be x
Price = x/0.8= 1.25x
Dye is 60% of unit costs= 0.6x
Cost of remaining material= 1 - 0.6x = 0.4x
Unit Cost= Cost of Dye+ Cost of remaining material
So, in order to become unprofitable, Unit Cost must be 1.25x
Therefore
1.25x= Maximum cost of dye+ 0.4x
Maximum Cost of Dye = (1.25-0.4)x = 0.85x
Percentage change in cost of dye= {(0.85x-0.6x)/0.6x}*100= 41.66 or 42%
Therefore, theowest percentage increase in the cost of dye that would make the scarves unprofitable is 42%.
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Answer:
27
Step-by-step explanation:
Number of member of staff that drank tee = total number of member of staff - number that drank coffee - number that drank both tea and coffee
100 - 48 - 25 = 27 members of staff
welll i kinda don get ur question but ummmm if u say like the graetest number then 48
To solve the problem we could separate the figure into three parts. First figure is a triangle, second figure is a rectangle, third figure is a triangle. See image attached.
Solve each area of the figuresFirst figure, a triangle that have 7 units long of the base, and 2 units long of the height.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the first figure is 7 units²
Second figure is a rectangle, the length of the rectangle is 7 units, the width of the rectangle is 4 units.
a = l × w
a = 7 × 4
a = 28
The area of the second figure is 28 units²
Third figure is a triangle, the base is 7 units long and the height is 2 units long.
a = 1/2 × b × h
a = 1/2 × 7 × 2
a = 14/2
a = 7
The area of the third figure is 7 units²
The area of the three figuresarea = first figure area + second figure area + third figure area
area = 7 + 28 + 7
area = 42
The total area of the figures is 42 units²