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Colt1911 [192]
3 years ago
11

Prove that (n+5)^2 - (n+3)^2 is a multiple of 4 for all positive integer values of n.

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

Answer:

(n+5)² - (n+3)² =

= (n² + 10n + 25) - (n² + 6n + 9)

= n² + 10n + 25 - n² - 6n - 9

= 4n + 16

= 4(n + 4) ⋮ 4

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8 0
4 years ago
The first three terms of an arithmetic sequence are as follows.-1, 3, 7Find the next two terms of this sequence
Schach [20]
<h2>Answer:</h2>

11 and 15

<h2>Explanations:</h2>

Given the arithmetic sequence -1, 3, 7 __, __, you are to find the next two terms of the sequence.

The nth term of an arithmetic sequence is given as;

T_n=a+(n-1)d

where:

• a is the ,first term

,

• n is the ,number of terms

,

• d is the ,common difference

From the given sequence;

a = -1

d = 3 - (-1) = 7 - 3 = 4

For the fourth term, n = 4;

\begin{gathered} T_4=-1+(4-1)\cdot4 \\ T_4=-1+3(4) \\ T_4=-1+12 \\ T_4=11 \end{gathered}

For the fifth term, n = 5;

\begin{gathered} T_5=-1+(5-1)\cdot4 \\ T_5=-1+4(4) \\ T_5=-1+16 \\ T_5=15 \end{gathered}

Therefore the next two terms of the arithmetic sequence are 11 and 15.

8 0
1 year ago
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