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Sedaia [141]
3 years ago
8

Here is a histogram displaying the top 30 lifetime batting averages in baseball history. This distribution of data shows lots of

lifetime averages in the middle classes, but tails off sharply at both the upper and lower ends. What best explains the fact that there are very few averages in the lowest class?
A. There may be other hitters in the 320s, but they didn't make the top 30.
B. Very few batters are skillful enough to have the very highest batting averages.
C. Batting averages lie on a bell-shaped curve.
D. The histogram is symmetrical.
E. Histograms always have taller bars in the middle.
Mathematics
2 answers:
vovangra [49]3 years ago
7 0
I believe the answer is A.
exis [7]3 years ago
7 0

ANSWER:

The correct answer is A. There may be other hitters in the 320s, but they didn't make the top 30.

STEP-BY-STEP EXPLANATION:

Here is a histogram displaying the top 30 lifetime batting averages in baseball history. This distribution of data shows lots of lifetime averages in the middle classes, but tails off sharply at both the upper and lower ends. What best explains the fact that there are very few averages in the lowest class?

The correct answer is A. There may be other hitters in the 320s, but they didn't make the top 30.

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3 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

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Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

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Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

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Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
4 years ago
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pickupchik [31]

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4 0
3 years ago
Diego has two jobs. He works 3 hours at the library each day, making $8 per hour. In addition, he works at a coffee shop, making
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Answer:

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Step-by-step explanation:

<h3>Work at library</h3>
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Correct option is D

3 0
3 years ago
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