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Shalnov [3]
4 years ago
7

If line segment AB is the perpendicular bisector of line segment XY at point P,

Mathematics
1 answer:
luda_lava [24]4 years ago
4 0

Answer: xp=py

<xpa=<apy

4 right angles are formed

2(xp)=xy

<xpa and <apy are supplements.

Step-by-step explanation:

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Opposite angles of an inscribed quadrilateral are supplementary?
tangare [24]

Answer:

yes

Step-by-step explanation:

according to cyclic quadrilateral properties the oppoaite angles are supplementry

4 0
3 years ago
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Y_Kistochka [10]

Step-by-step explanation:

multiply.48 by 55and then divide it by the swuare root

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3 years ago
One stack has 6 cups, and its height is 15 cm. The other one has 12 cups, and its height is 23 cm. How many cups are needed for
Ronch [10]

Answer:

Given

Number of stacks = 2

Stack 1 = 6 cups; h1 = 15cm

Stack 2 = 12 cups; h2 = 23cm

Let's first find the average:

With an average of 4/3, to obtain the number of cups needed to obtain a height of 50m, we have:

50 / (4/3)

= 50 * 3/4

= 150/4

= 37.5

From the answer, we can see that the number of cups is not really proportional to the height of the stack, because the average of stack one and stack 2 are different.

Step-by-step explanation:

7 0
3 years ago
Tico Wartboot
Lorico [155]
The farmer sends 15 pounds to the local market.
8 0
2 years ago
Eight adults and two children need to cross a river. A small boat is available that can hold one adult or one or two children. E
sleet_krkn [62]

Answer:

A = 8, C = 2 => T = 33

A=100, C = 2 => T = 401

A = any, C = 2 => T = 4A + 1

A = 8, C = 4 => T = 37

As long as the boat can carry one adult or one or two children, the following equation should solve the problem.

T = 4A + 2(C-2) + 1

Step-by-step explanation:

To transfer one adult, 4 one-way trips need to be made as follows:

1. Two children cross the river

2. One of them takes the boat back to the other side

3. One adult crosses the river

4. The other child takes the boat back

These four steps are repeated until all adults are crossed. At this point no children has crossed yet.

Then for every 2 children except the last 2, 2 one-way trips need to be made if the number of children is greater than 2:

1. Two children cross

2. One takes the boat back

For the last 2,only one trip needs to be made.

A = number of adults

C = number of children >= 2

T = total trips

T = 4A + 2(C-2) + 1

4 0
3 years ago
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