probably choice D is the most trust worthy but if im right please tell me
<span>1) Multiply both sides of the equation by 2:
2(A)=2[1/2h(b+c)
2A=2/2h(b+c)
2A=1h(b+c)
2A=h(b+c)
2) Divide both sides of the equation by (b+c):
(2A)/(b+c)=[h(b+c)]/(b+c)
2A/(b+c)=h
h=2A/(b+c)
Answer: </span>
Hello,
x=3+2y
==> 3(3+2y)²-5(3+2y)y-16y=24
==>2y²+5y+3=0
==>(y=-3/2 and x= 0 or y=-1 and x=1)
sol={(0,-3/2),(1,-1)}