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Marizza181 [45]
3 years ago
7

I need to know how to find angle "H"

Mathematics
1 answer:
vazorg [7]3 years ago
5 0
Check the picture below.  Recall your SOH CAH TOA.

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A rectangular beam will be cut from a cylindrical log of radius 10 inches.
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b

Step-by-step explanation:

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Find the total surface area of this triangular prism,<br> 30 cm<br> 18 cm<br> 7 cm<br> 24 cm
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2 years ago
What is the percent increase of 10 to 24?
Aleks [24]
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3 years ago
Read 2 more answers
Solve for x in the equation x squared minus 4 x minus 9 = 29. x = 2 plus-or-minus StartRoot 42 EndRoot x = 2 plus-or-minus Start
Furkat [3]

Answer:

x=2$\pm$\sqrt{42}

Step-by-step explanation:

The given equation is:

x^{2} -4x-9=29\\\Rightarrow x^{2} -4x-9-29=0\\\Rightarrow x^{2} -4x-38=0

<u>Formula:</u>

A quadratic equation ax^{2} +bx+c=0 has the following roots:

x=\dfrac{-b+\sqrt D}{2a}\ and\\x=\dfrac{-b-\sqrt D}{2a}

Where D= b^{2} -4ac

Comparing the equation with ax^{2} +bx+c=0

a = 1

b = -4

c= -38

Calculating D,

D= (-4)^{2} -4(1)(-38)\\\Rightarrow D = 16+152 = 168

Now, finding the roots:

x=\dfrac{-(-4)+\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4+2\sqrt {42}}{2}\\\Rightarrow x=2+\sqrt {42}\\and\\x=\dfrac{-(-4)-\sqrt {168}}{2\times 1}\\\Rightarrow x=\dfrac{4-2\sqrt {42}}{2}\\\Rightarrow x=2-\sqrt {42}

So, the solution is:

x=2$\pm$\sqrt{42}

5 0
2 years ago
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