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3 years ago

Please help me. I'm desperate

Mathematics

1 answer:

Flauer [41]3 years ago

7 0

Ok so x is the original price and we want to solve if the original price was 48 so x=48. When we substitute this into the equation we get 0.75(48)-0.15(0.75x48). When we simplify this expression we get 30.6. The current price is $30.60. Hope this helps.

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Find the measures of: all angles if 3(m∠1+m∠3) = m∠2+m∠4

slavikrds [6]

Answer:

Part 1) m∠1=45°

Part 2) m∠3=45°

Part 3) m∠2=135°

Part 4) m∠4=135°

Step-by-step explanation:

we know that

m∠1=m∠3 -----> by vertical angles Equation A

m∠2=m∠4 -----> by vertical angles Equation B

m∠1+m∠2=180° ----> by supplementary angles (linear pair) Equation C

3(m∠1+m∠3) = m∠2+m∠4 ----> Equation D

Substitute equation A and equation B in equation D

3(m∠1+m∠1) = m∠2+m∠2

6(m∠1) = 2m∠2

3(m∠1) =m∠2 -----> equation E

Substitute equation E in equation C and solve for m∠1

m∠1+3(m∠1)=180°

4(m∠1)=180°

m∠1=45°

Find the measure of m∠3

Remember that

m∠1=m∠3 (equation A)

therefore

m∠3=45°

Find the measure of m∠2

Remember that

m∠2=3(m∠1) (equation E)

substitute the value of m∠1

m∠2=3(45°)=135°

Find the measure of m∠4

Remember that

m∠2=m∠4 (equation B)

therefore

m∠4=135°

4 0

3 years ago

A cyclist rides her bike at a rate of 21 kilometers per hour. What is this rate in kilometers per minute? How many kilometers

Dafna11 [192]

Answer:

Step-by-step explanation:

4 0

3 years ago

John and Tim are looking at the equation the square root of the quantity of 3 times x minus 4 equals square root of x . John say

IgorC [24]

The equation is
3x - 4 = sqrt(x)
where 'sqrt' is shorthand for 'square root'

Let's solve the equation. To do so, we square both sides. Then we get everything to one side
3x - 4 = sqrt(x)
(3x - 4)^2 = (sqrt(x))^2
9x^2 - 24x + 16 = x
9x^2 - 24x + 16-x = x-x
9x^2 - 25x + 16 = 0

Now use the quadratic formula. See the attached image for those steps.

After using the quadratic formula the two possible solutions are x = 1 or x = 16/9

We need to check each possible solution to see if it is extraneous or not.

----------------------------

Checking x = 1

3x - 4 = sqrt(x)
3*1 - 4 = sqrt(1)
3 - 4 = 1
-1 = 1

The final equation is false, so x = 1 is not a true solution

x = 1 is extraneous.

So far, John is correct; however, we need to see the nature of the possible solution x = 16/9

So let's check it
----------------------------

Checking x = 16/9

3x - 4 = sqrt(x)
3*(16/9) - 4 = sqrt(16/9)
48/9 - 4 = 4/3
16/3 - 4 = 4/3
16/3 - 12/3 = 4/3
(16 - 12)/3 = 4/3
4/3 = 4/3

The last equation is true, so x = 16/9 is a proper solution.

This solution is considered non-extraneous. So Tim is also correct
----------------------------

They are both correct because there are two possible solutions. One of which is extraneous (x = 1) and the other is non-extraneous (the fraction x = 16/9)