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Ivenika [448]
4 years ago
7

Polygon ABCD reflects about line MN to make polygon EFGH. What is the length of FG?

Mathematics
2 answers:
Anni [7]4 years ago
6 0

Answer:

2

Step-by-step explanation:

I just did this on plato :))

Delicious77 [7]4 years ago
4 0

Answer:

The correct answer is option A.

Step-by-step explanation:

Given : Polygon ABCD reflects about line MN to make polygon EFGH

To find = FG = ?

Solution.

Polygon formed by the reflection of polygon ABCD will have same measurement of length for each corresponding sides.

AB = EF = 3 units

BC = FG = 2 units

CD = GH = 2.2 units

AD = EH = 3.2 units

So, the length of FG is 2 units.

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PLS HELP AND EXPLAIN IT IS PROBABILITY :) oops sorry for caps
Taya2010 [7]

Answer:

1/18 or 0.0555... or %5.555...

Step-by-step explanation:

<u>Step 1:  Find the probability of choosing a 1</u>

1 out of 6 → 1/6

<u>Step 2:  Find the probability of choosing a blue chip.</u>

2 out of 6 → 2/6 → 1/3

<u>Step 3:  Multiply it</u>

1/6 * 1/3

1/18

Answer: 1/18 or 0.0555... or %5.555...

3 0
4 years ago
3845 divided by 0.07. Round to the nearest tenth.
IRINA_888 [86]

Answer: 55357.1


Step-by-step explanation: When you divide 3845 by 0.07 you get 553571.142857142857143. TTo round to the nearest tenth means the first decimal point which woukd make the answer 55357.1


5 0
3 years ago
What is the lcm of 24de^2 and 36d^3e
lisov135 [29]
The lcm of this is 6d
7 0
4 years ago
A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f
NNADVOKAT [17]

Answer:

26 - \sqrt{181} cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares,  in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}

x = \frac{624 \pm \sqrt{104256}}{24}

x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}

x = \frac{624 \pm 8*3*\sqrt{181}}{24}

x_1 = \frac{624 + 24*\sqrt{181}}{24}

x_1 = 26 + \sqrt{181}

x_2 = \frac{624 - 24*\sqrt{181}}{24}

x_2 = 26 - \sqrt{181}

But x_1 > 33, then is not the correct answer.

5 0
3 years ago
100 Points!!!
inessss [21]

Answer:

An object moving along the x-axis is said to exhibit simple harmonic motion if its position as a function of time varies as

x(t) = x0 + A cos(ωt + φ).

The object oscillates about the equilibrium position x0.  If we choose the origin of our coordinate system such that x0 = 0, then the displacement x from the equilibrium position as a function of time is given by

x(t) = A cos(ωt + φ).

A is the amplitude of the oscillation, i.e. the maximum displacement of the object from equilibrium, either in the positive or negative x-direction.  Simple harmonic motion is repetitive.  The period T is the time it takes the object to complete one oscillation and return to the starting position.  The angular frequency ω is given by ω = 2π/T.  The angular frequency is measured in radians per second.  The inverse of the period is the frequency f = 1/T.  The frequency f = 1/T = ω/2π of the motion gives the number of complete oscillations per unit time.  It is measured in units of Hertz, (1 Hz = 1/s).

The velocity of the object as a function of time is given by

v(t) = dx(t)/dt = -ω A sin(ωt + φ),

and the acceleration is given by

a(t) = dv(t)/dt = -ω2A cos(ωt + φ) = -ω2x.

4 0
3 years ago
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