Question

Simplify the expression

Answer 1

Answer:

B.

Step-by-step explanation:

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Answer 2

Answer:

D

Step-by-step explanation:

$\frac{\frac{b^{2}+5b+6}{3bc}}{\frac{b^{2}-9}{6bc}}\\\\=\frac{b^{2}+5b+6}{3bc}*\frac{6bc}{b^{2}-9}\\\\=\frac{(b+3)*(b+2)}{3bc}*\frac{6bc}{b^{2}-3^{2}}\\\\=\frac{(b+3)*(b+2)}{3bc}*\frac{6bc}{(b+3)(b-3)}\\\\=\frac{(b+2)*2}{(b-3)}\\\\=\frac{2(b+2)}{(b-3)}$

Hint: b ²+ 5b + 6 = b² + 3b + 2b + 2*3

                          = b*(b + 3) + 2*(b + 3)

                         = (b + 3) (b + 2)

x² - y² = (x  + y)(x - y)

b² - 9 = b² - 3² = (b + 3) (b -3)