Chance to draw 7: 4 out of 52
chance to draw 1st queen: 4 out of 51
chance to draw 2nd queen: 3 out of 50
total chance = multiplication of
times
times
pretty miserable change... apox 1 out of 2762, but still much better than any lottery ticket
<span>Area of circular metal=πr^2
=3.14 x 3.5 x 3.5 m^2
now,
total cost=area x rate
=3.14 x 3.5 x 3.5 x 3.25 $
=125.01 $</span>
Answer:
<em>615.44m²</em>
Step-by-step explanation:
The base of the silo is a circle
Rea of the base of the silo = πr²
r is the radius of the silo
Given
radius r = 14m
Area of the base of the silo = π(14)²
Area of the base of the silo = 3.14(196)
Area of the base of the silo = 615.44
<em>Hence the area of the base of the silo is 615.44m²</em>
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
