PLEASE HELP ASAP I'M ON THE TEST RIGHT NOW AND IT'S DUE TODAY!! The box plot shows the algebra scores of students in class A and
class B
The median score of class A is ____
The interquartile range of class B is ____
The difference of the medians of class A and class B is ____ the interquartile range of either data set
The median score of class A is ____
The interquartile range of class B is ____
The difference of the medians of class A and class B is ____ the interquartile range of either data set
1 answer:
You might be interested in
The correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
<h3>Solving inequality</h3>From the question, we are to solve the inequality
The given inequality is
–3(2x – 5) < 5(2 – x)
First, clear the brackets
–6x + 15 < 10 – 5x
NOTE: This is one of the correct representations of the inequality
Collect like terms
-6x + 5x < 10 - 15
-x < -5
Divide both sides by -1 and flip the sign
x > 5
Representing this on a number line, we get a number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is pointing to the right.
Hence, the correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
Learn more on Inequalities here: brainly.com/question/246993
#SPJ1
Answer:
126 hrs
Step-by-step explanation:
-Given the school year has 180 days and the non-working student spends 42 minutes more than the working student.
-The total time during the school year is calculated as;
We convert our calculated time in hour(1hr=60 minutes):
Hence, the average non-working spends an average of 126 hrs that the working student.