Answer:
D is the answer. There are 5 boxes, that each has 3 filled in.
Hey there! :)
Since 2 4/5 is greater than 1/4, the answer is negative.
You can just subtract 2 4/5 and 1/4 and add the (-) sign
2 4/5 - 1/4
Change the fractions so they can have a common denominator: 20
2 4/5 = 2 16/20
1/4 = 5/20
2 16/20 - 5/20 = 2 11/20
Add the (-) sign → -2 11/20
Answer ⇒ -2 11/20
:)
Answer:
False (under assumption T(2,-3) means move it right 2 units and down 3 units).
Step-by-step explanation:
The statement is false.
T(2,-3) means move the point right 2 (so plus 2 on the x-coordinate) and down 3 units (so minus 3 on the y-coordinate).
So (1,6) will become (1+2,6-3)=(3,3) after the translation.
The point (1,12) will become (1+2,12-3)=(3,9).
If the statement were "Under the translation T(2,-3) the point (1,12) will become (3,9)", then it would be true.
Or!
If the statement were "Under the translation T(2,3) the point (1,6) will become (3,9)", then it would be true.
Answer:
<h2>2x-10 = 65-x</h2><h2 />
Step-by-step explanation:
just add up both alternate internal angles as they are both equal
so, the equation is: 2x-10 = 65-x
Piecewise Function is like multiple functions with a speific/given domain in one set, or three in one for easier understanding, perhaps.
To evaluate the function, we have to check which value to evalue and which domain is fit or perfect for the three functions.
Since we want to evaluate x = -8 and x = 4. That means x^2 cannot be used because the given domain is less than -8 and 4. For the cube root of x, the domain is given from -8 to 1. That meand we can substitute x = -8 in the cube root function because the cube root contains -8 in domain but can't substitute x = 4 in since it doesn't contain 4 in domain.
Last is the constant function where x ≥ 1. We can substitute x = 4 because it is contained in domain.
Therefore:
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 8} \\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%208%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
The nth root of a can contain negative number only if n is an odd number.
![\large{ \begin{cases} f( - 8 ) = \sqrt[3]{ - 2 \times - 2 \times - 2} \\ f(4) = 3 \end{cases}} \\ \large{ \begin{cases} f( - 8 ) = - 2\\ f(4) = 3 \end{cases}}](https://tex.z-dn.net/?f=%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20%20%5Csqrt%5B3%5D%7B%20-%202%20%5Ctimes%20-%20%202%20%5Ctimes%20%20%20-%202%7D%20%20%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D%20%5C%5C%20%20%5Clarge%7B%20%20%5Cbegin%7Bcases%7D%20f%28%20-%208%20%29%20%3D%20%20-%202%5C%5C%20f%284%29%20%3D%203%20%5Cend%7Bcases%7D%7D)
Answer
