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Hitman42 [59]
3 years ago
10

Helllpppppppppp please someone.?????

Mathematics
1 answer:
Liula [17]3 years ago
6 0

Answer:

(-5,5)

Step-by-step explanation:

Multiply the first equation by -2,and multiply the second equation by 1.

−2(x+5y=20)

1(2x−7y=−45)

Becomes:

−2x−10y=−40

2x−7y=−45

Add these equations to eliminate x:

−17y=−85

Then solve−17y=−85for y:

(Divide both sides by -17)

y=5

x+5y=20

Substitute  5 for y in x+5y=20:

x+(5)(5)=20

x+25=20(Simplify both sides of the equation)

x+25+−25=20+−25(Add -25 to both sides)

x=-5

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Write four different facts from 2,3 5
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6 0
3 years ago
Meg deposited a $3,000 bonus check in a new savings account. The account has an interest rate of 3% for 5 years. The interest is
Nataly [62]

Answer:

The $3485.52 money did Meg have at the end of the account term.

Step-by-step explanation:

Formula for compounded monthly

Amount = P(1+\frac{r}{365})^{365n}

Where P is the principle , r is the rate of interest in the decimal form and n is the number of years.

As given

Meg deposited a $3,000 bonus check in a new savings account. The account has an interest rate of 3% for 5 years.

Principle = $3000

3% is written in the decimal form

= \frac{3}{100}

= 0.03

Time = 5 years

Put in the formula

Amount = 3000(1+\frac{0.03}{365})^{365\times 5}

Amount = 3000(1+\frac{0.03}{365})^{1825}

Amount = 3000(1+\frac{0.03}{365})^{1825}

Amount = 3000(1+ 0.0000822)^{1825}

Amount = 3000(1.0000822)^{1825}

Amount = 3000\times 1.16184

Amount = $ 3485.52

Therefore the  $ 3485.52  money did Meg have at the end of the account term.




4 0
3 years ago
Read 2 more answers
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