Question

Find the x value for point C such that AC and BC form a 2:3 ratio.

Answer 1

Answer:

B. $-0.6$

Step-by-step explanation:

We have been given point C divides A and B such that AC and BC form a 2:3 ratio.

We will use section formula to solve our given problem, which states when a point P internally divides segment AB is ration m:n, then

$[x=\frac{m*x_2+n*x_1}{m+n},y=\frac{m*y_2+n*y_1}{m+n}]$

Upon substituting our given values we will get,

$[x=\frac{2*3+3*-3}{2+3},y=\frac{2*0+3*5}{2+3}]$

$[x=\frac{6-9}{5},y=\frac{0+15}{5}]$

$[x=\frac{-3}{5},y=\frac{15}{5}]$

$[x-0.6,y=3]$

Therefore, the value of x is $-0.6$ and option B is the correct choice.

Answer 2

The answer is B.-0.6