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Ulleksa [173]
3 years ago
7

Ariel wants to write 8 entries for her blog. After 2 hours, she has 5 entries left. After 4 hours, she has 2 entries left. Which

graph represents Ariel's remaining entries?
graph of line going through (0, 0) with a slope of 1.5

graph of line going through (0, 2) with a slope of 2

graph of line going through (0, 8) with a slope of 1.5

graph of line going through (0, 3) with a slope of 3

Mathematics
2 answers:
Mrac [35]3 years ago
8 0

Answer:

Graph of line going through (0, 8) with a slope of 1.5  represents Ariel's remaining entries

Step-by-step explanation:

Ariel wants to write 8 entries for her blog.

After 2 hours, she has 5 entries left. (x_1,y_1)=(2,5)

After 4 hours, she has 2 entries left. (x_2,y_2)=(4,2)

So, now using two point slope form:

y-y_1=m(x-x_1) ---1

where m = \frac{y_2-y_1}{x_2-x_1}

So , substituting the given points we get the equation that represents the given situation .

m = \frac{2-5}{4-2}

m = \frac{-3}{2}

m = -1.5

Now,

y-5 = -1.5(x-2)

y-5 = -1.5x+3

Thus the slope of the given situation is 1.5

Now at x = 0

y-5 = -1.5*0+3

y=8

So, at 0 hour 8 entries left .

So, graph of line going through (0, 8) with a slope of 1.5  represents Ariel's remaining entries

Komok [63]3 years ago
3 0
After 2 hours she wrote 3 entries.
after 4 hours she wrote 6 entries.
This means that for same period she is writing same number of entries which means her "writing speed" is constant.
that means that graph is linear function (straight line).

slope we calculate by putting coordinates of y and x of any dot on that line. we can use one of those given by text of task. (in 2 hours she wrote 3 entries)
y = k*x
k = y/x
k = 1.5

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Step-by-step explanation:

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The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
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