Question

A company provides bus trips to various events for a adults and c children. The company charges $18 for each adult and $8 for each child for a trip to an upcoming play. The bus has a maximum capacity of 40 people and the school can only spend $400 dollars on the trip. Write and solve a system of equations to determine the maximum number of adults and children that can attend the play that will satisfy these constraints.

Answer 1

The maximum number of adults is 8 and children is 32 .

Step-by-step explanation:

Let the number of adults  be-----------x, where x>0

Let the number of children be---------y, where y>0

Charges for an adult per trip = $18

Charges for a child per trip = $8

Total number of people a bus can carry = 40

The inequality for total number of people a bus can carry will be;

x+y ≤ 40 ...............(i)

The school can only spend $400 on the trip, thus the inequality for cost of trip will be;

$18 x + $8 y ≤ $400

18 x + 8 y ≤ 400 -----------(ii)

Using a graph tool to plot the inequalities and view the results gives the attached graph

From the graph, x= 8  and y=32

The maximum number of adults is 8 and children is 32 .

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Inequalities solutions by graph:brainly.com/question/13334731

Keywords: company, bus trips, events, adults, children, charges, maximum capacity, system of equations

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