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Montano1993 [528]
3 years ago
15

Given h(x) = -x - 5, find h(0)​

Mathematics
2 answers:
fenix001 [56]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

you plug in zero for x and then just solve.

h(0)=-0-5

=-5

pogonyaev3 years ago
3 0
Steps:
h(0) = -(0)-5
-(0)-5
0-5
-5
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For what value of a are the lines of 6y=-2x+4 and 2y=ax-5 parallel? perpendicular?
masha68 [24]

Hey there!!

Parallel lines have the same slope. If they have different slope, then they are not parallel because both lines would combine at some point.

The y-intercept form:

<em>y = mx + b </em>

<u>In this equation, 'm' is considered to be the slope. </u>

The equation we have is 6y = -2x + 4

First, let's divide all the sides with 6 to isolate the value of 'y'.

... 6y = -2x + 4

... y = -1/3x + 2/3

<u><em>The slope is -1/3... </em></u>

<u><em>... hence the slope in the other equation should be -1/3. </em></u>

Equation we got...

... 2y = ax - 5

Let's divide by 2 on both sides...

... y = ax/2 - 5

The slope in this a/2

<u><em>Hence, ... </em></u>

<u><em>... a/2 = -1/3 </em></u>

<u><em>... 3a = -2 </em></u>

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4 0
3 years ago
(4x – 8)(3x + 9) = 0​
Gwar [14]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=2,\:x=-3

Step-by-step explanation:

Considering the equation

                         \left(4x\:-\:8\right)\left(3x\:+\:9\right)\:=\:0

solving the equation

\left(4x\:-\:8\right)\left(3x\:+\:9\right)\:=\:0

\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

\mathrm{Solve\:}\:4x-8=0

4x-8=0

4x-8+8=0+8

4x=8

x=2

\mathrm{Solve\:}\:3x+9=0

3x+9=0

3x+9-9=0-9

3x=-9

x=-3

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=2,\:x=-3

4 0
3 years ago
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